DWG NO. 12.5 — Lesson 5 of 5

Equations of Circles

Unit 12: Circles · ~15–30 min

Objective

Write the standard-form equation of a circle given its center and radius, and identify the center and radius from an equation, including one that needs completing the square.

Standard form

Back in Lesson 12.1, a circle was defined as every point the same distance from a center. On the coordinate plane, that distance statement translates directly into an equation using the distance formula. For a circle with center (h, k) and radius r, the standard form equation is:

(x − h)² + (y − k)² = r²

Every point (x, y) that makes this equation true is exactly r units from (h, k) — which is precisely the definition of the circle.

(h, k) r (x, y)

Any point (x, y) on the circle is a distance r from center (h, k).

Completing the square

Sometimes a circle's equation is given in expanded form, like x² + y² + Dx + Ey + F = 0. To find the center and radius, group the x-terms and y-terms and complete the square on each group to force the equation back into standard form.

Worked Example 1 · Writing an equation
ProblemWrite the standard-form equation of a circle with center (−3, 4) and radius 7.
1.Substitute h = −3, k = 4, r = 7 into (x − h)² + (y − k)² = r².
2.(x − (−3))² + (y − 4)² = 7² becomes (x + 3)² + (y − 4)² = 49.
(x + 3)² + (y − 4)² = 49
Worked Example 2 · Completing the square
ProblemFind the center and radius of the circle x² + y² − 6x + 8y + 9 = 0.
1.Group x-terms and y-terms, moving the constant to the right: (x² − 6x) + (y² + 8y) = −9.
2.Complete the square for x: half of −6 is −3, squared is 9. Complete the square for y: half of 8 is 4, squared is 16. Add both to each side: (x² − 6x + 9) + (y² + 8y + 16) = −9 + 9 + 16.
3.Factor and simplify: (x − 3)² + (y + 4)² = 16.
Center (3, −4), radius 4

Guided practice

In-person Review & Practice Day 12Not a web page — work problems, ask questions, get feedback in class.