DWG NO. 12.1 — Lesson 1 of 5

Circle Vocabulary and Central Angles

Unit 12: Circles · ~15–30 min

Objective

Identify the parts of a circle and find the measure of a central angle or its intercepted arc.

Defining a circle

A circle is the set of all points in a plane that are the same distance — the radius — from a fixed point called the center. Everything in this unit follows from that single idea: one center, one distance, and every point that satisfies it.

Parts of a circle

TermDefinition
CenterThe fixed point every point on the circle is equidistant from. Circles are named by their center (circle O).
RadiusA segment from the center to any point on the circle. All radii of the same circle are congruent.
DiameterA chord that passes through the center; its length is twice the radius (d = 2r).
ChordA segment whose endpoints both lie on the circle. A diameter is the longest possible chord.
Central angleAn angle whose vertex is the center of the circle and whose sides are two radii.
ArcA piece of the circle between two points on it, measured in degrees.

Central angles and their arcs

Every central angle "cuts off" or intercepts an arc, and the two share the same measure — a central angle of 70° always intercepts an arc of 70°. Arcs come in three flavors:

Arc Addition Postulate: the measure of an arc formed by two adjacent arcs is the sum of the two arc measures — the same idea as the Angle Addition Postulate, just wrapped around a circle.

O A B 70° arc AB

Central angle AOB measures 70°, so its intercepted minor arc AB also measures 70°.

Worked Example 1 · Minor and major arc
ProblemIn circle O, central angle AOB measures 84°. Find the measure of minor arc AB and major arc AB.
1.A central angle and its intercepted (minor) arc always have equal measure, so minor arc AB = 84°.
2.The major arc is the rest of the circle: 360° − 84° = 276°.
Minor arc AB = 84°; major arc AB = 276°
Worked Example 2 · Arc addition
ProblemPoints A, B, and C lie on circle O in that order. Arc AB = 3x°, arc BC = 5x°, and arc AC (the major arc, going the other way through the top) is a semicircle’s worth combined with AB and BC to complete the circle: arc AB + arc BC + arc CA = 360°, where arc CA = 130°.
1.Substitute: 3x + 5x + 130 = 360.
2.Combine and solve: 8x + 130 = 360, so 8x = 230, x = 28.75.
3.Then arc AB = 3(28.75) = 86.25° and arc BC = 5(28.75) = 143.75°.
x = 28.75; arc AB = 86.25°, arc BC = 143.75°

Guided practice