DWG NO. 06.1 — Lesson 1 of 5

Polygon Interior/Exterior Angle Sums

Unit 6: Quadrilaterals and Polygons · ~15–30 min

Objective

Find the sum of interior angles, the sum of exterior angles, and individual angle measures for any polygon.

Splitting a polygon into triangles

Every polygon can be cut into triangles by drawing diagonals from a single vertex. A triangle's angles always sum to 180°, so counting how many triangles fit inside a polygon tells you the polygon's total interior angle sum. An n-sided polygon splits into exactly n − 2 triangles this way.

For a regular polygon (all sides and angles congruent), divide each sum evenly across the n vertices to get one interior or one exterior angle.

3 triangles

A pentagon (n = 5) splits into 3 triangles from one vertex — interior sum = 3(180°) = 540°.

Worked Example 1 · Interior angle sum
ProblemFind the sum of the interior angles of a heptagon (7 sides).
1.Use (n − 2) · 180° with n = 7: (7 − 2) · 180° = 5 · 180°.
2.5 · 180° = 900°.
Interior angle sum = 900°
Worked Example 2 · Each angle of a regular polygon
ProblemFind the measure of each interior and each exterior angle of a regular decagon (10 sides).
1.Interior sum = (10 − 2) · 180° = 1440°. Each interior angle = 1440° ÷ 10 = 144°.
2.Exterior sum is always 360°, so each exterior angle = 360° ÷ 10 = 36°. Check: 144° + 36° = 180°, a straight line. ✓
Each interior angle = 144°, each exterior angle = 36°

Guided practice