DWG NO. 05.3 — Lesson 3 of 5

Medians, Altitudes, and Points of Concurrency

Unit 5: Relationships Within Triangles · ~15–30 min

Objective

Identify a triangle's four special centers and apply the centroid's 2:1 ratio to find median lengths.

Every triangle has four families of special segments, and each family always meets at a single point — a point of concurrency. The table below is the map: which segment, which point, which guarantee.

SegmentDefinitionMeeting pointKey property
Perpendicular bisectorsBisects each side at 90°CircumcenterEquidistant from the three vertices; can fall inside, outside, or on the triangle
Angle bisectorsBisects each angleIncenterEquidistant from the three sides; always inside the triangle
MediansVertex to the midpoint of the opposite sideCentroidThe triangle's balance point; always inside
AltitudesVertex, perpendicular to the opposite side (or its extension)OrthocenterCan fall inside, outside, or on the triangle

The centroid's 2:1 ratio

The centroid deserves special attention because it comes with a numeric guarantee the others don't: it always divides each median into two pieces with a 2:1 ratio, measured from the vertex.

A M G 2 parts 1 part

Centroid G divides median AM so that AG is twice GM.

Worked Example 1 · Find a piece of the median
ProblemMedian AM = 21, and G is the centroid. Find AG and GM.
1.The centroid splits the median 2:1, so AM splits into 3 equal parts total — 2 parts for AG, 1 part for GM.
2.Each part = 21 ÷ 3 = 7. So AG = 2(7) = 14, and GM = 7.
AG = 14, GM = 7
Worked Example 2 · Solve for the whole median
ProblemG is the centroid, and CG = 16. Find the full length of median CN.
1.CG is the "2 parts" segment from the vertex to the centroid, so CG = ⅔ of CN.
2.16 = ⅔CN, so CN = 16 × &frac32; = 24.
CN = 24

Guided practice