DWG NO. 03.1 — Lesson 1 of 4

Transversals and Angle Relationships

Unit 3: Parallel and Perpendicular Lines · ~15–30 min

Objective

Identify the angle pairs formed when a transversal crosses two lines, and use the parallel-line angle theorems to find unknown angle measures.

A transversal and its angle pairs

A transversal is a line that crosses two (or more) other lines at two distinct points. Where it crosses each line, it creates four angles — eight angles total — and those eight angles fall into four named relationships depending on where they sit relative to the two lines and the transversal.

Pair typeWhere they sitIf the two lines are parallel
CorrespondingSame position at each intersection (both upper–left, both lower–right, etc.)Congruent
Alternate interiorBetween the two lines, on opposite sides of the transversalCongruent
Alternate exteriorOutside the two lines, on opposite sides of the transversalCongruent
Consecutive interiorBetween the two lines, on the same side of the transversalSupplementary
m n t P Q 1 2 3 4 5 6 7 8

Transversal t crosses lines m and n at P and Q, forming angles 1–4 at P and 5–8 at Q.

The parallel-line angle theorems

These relationships only guarantee congruence or supplementary angles when the two lines cut by the transversal are parallel. That condition matters — it's the hinge the next lesson turns on.

Worked Example 1 · Finding every angle
ProblemIn the diagram above, line m ∥ line n and angle 3 = 115°. Find the measures of angles 1, 2, 4, 5, 6, 7, and 8.
1.At point P, angle 3 and angle 1 form a linear pair (they're supplementary): angle 1 = 180° − 115° = 65°. Angle 4 is vertical to angle 1, so angle 4 = 65°. Angle 2 is vertical to angle 3, so angle 2 = 115°.
2.Angle 3 and angle 6 are alternate interior angles, so by the Alternate Interior Angles Theorem, angle 6 = 115°. Angle 4 and angle 5 are also alternate interior angles, so angle 5 = 65°.
3.At point Q, angle 7 is vertical to angle 6, so angle 7 = 115°. Angle 8 is vertical to angle 5, so angle 8 = 65°.
Angle 1 = 65°  •  Angle 2 = 115°  •  Angle 4 = 65°  •  Angle 5 = 65°  •  Angle 6 = 115°  •  Angle 7 = 115°  •  Angle 8 = 65°
Worked Example 2 · Solving for x
ProblemLine m ∥ line n. Angle 2 = (3x + 15)° and angle 6 = (5x − 25)°. Find x and the measure of angle 2.
1.Angle 2 and angle 6 occupy the same position at their intersections (both upper–right), so they are corresponding angles — and the lines are parallel, so they're congruent.
2.Set the expressions equal: 3x + 15 = 5x − 25.
3.Solve: 40 = 2x, so x = 20. Then angle 2 = 3(20) + 15 = 75°.
x = 20  •  Angle 2 = 75°

Guided practice