DWG NO. 02.5 — Lesson 5 of 5

Algebraic Proofs

Unit 2: Reasoning and Proof · ~15–30 min

Objective

Justify each step of an equation-solving or geometric proof using the properties of equality and the properties of congruence.

Properties of equality

These are the algebra rules you've used for years — now with formal names you'll cite as reasons in a proof.

PropertyMeaning
AdditionIf a=b, then a+c=b+c
SubtractionIf a=b, then a−c=b−c
MultiplicationIf a=b, then ac=bc
DivisionIf a=b and c≠0, then a÷c=b÷c
SubstitutionIf a=b, then a can replace b in any expression
Distributivea(b+c)=ab+ac
Reflexivea=a
SymmetricIf a=b, then b=a
TransitiveIf a=b and b=c, then a=c

Properties of congruence

Segments, angles, and other figures have their own parallel set: the Reflexive, Symmetric, and Transitive Properties of Congruence. They work exactly like their equality counterparts, just applied to congruence (≅) instead of equality (=) — for example, segment AB ≅ segment AB is true by the Reflexive Property of Congruence.

A C B AC CB AB

Segment Addition Postulate: if C is between A and B, then AC + CB = AB.

Worked Example 1 · Algebraic proof
ProblemSolve 3x − 7 = 2x + 5 for x, justifying each step.
1.3x − 7 = 2x + 5 — Given.
2.x − 7 = 5 — Subtraction Property of Equality (subtract 2x from both sides).
3.x = 12 — Addition Property of Equality (add 7 to both sides).
x = 12
Worked Example 2 · Segment addition proof
ProblemC is between A and B (as in the diagram above), with AC = 2x+3, CB = x−1, and AB = 20. Find x, AC, and CB.
1.AC + CB = AB — Segment Addition Postulate.
2.(2x+3) + (x−1) = 20 — Substitution.
3.3x + 2 = 20 — Simplify (combine like terms).
4.3x = 18 — Subtraction Property of Equality.
5.x = 6 — Division Property of Equality. Then AC = 2(6)+3 = 15 and CB = 6−1 = 5, and 15+5=20 checks out.
x = 6  •  AC = 15  •  CB = 5

Guided practice